On Fri, 18 Jan 2008 11:09:14 -0600 Paul Schmehl <[EMAIL PROTECTED]> wrote:
> I need to do the following: > > Take a list of various strings, one of which is a quoted IP address, and > extract the IPs. (Done that.) > > Then take the list of IPs and convert them to a list of IPs with masks on a > single line. > > IOW, I have converted the original list to this: > > x.x.x.x > x.x.x.x > x.x.x.x > x.x.x.x > > Now I need to remove the newlines and add /32, to the end of each IP so that > I > have this: > x.x.x.x/32,x.x.x.x/32,x.x.x.x/32,etc. > > I got close with sed, but I'm not quite there. > > I got this: > > x.x.x.x/32,x.x.x.x > x.x.x.x/32,x.x.x.x > x.x.x.x/32,x.x.x.x > > Here's the code I used: > cat hostlist | cut -d',' -f2 | cut -d'"' -f2 | sort | uniq | grep -v "inet" | > sed '/[^*]$/N;s/\n */\/32,/' > > What am I missing? I'm sure you'll get a lot of comments on this one ;-) Here's my one-liner take: while read line; do echo -n "${line}/32,"; done < hostlist | sed 's/\,$//' or to be a bit more understandable: while read line; do echo -n "${line}/32," done < hostlist | sed 's/\,$//' the little sed part just removes the last comma from the list. HTH, Randy -- _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "[EMAIL PROTECTED]"