If one has a system with 7 500Gb SATA disks in a hardware RAID6
(Areca Raid Controller), then (according to mail J.Chadwick 7
Nov 2008) they will show up as da (following naming convention
for scsi disks although they are not).
RAID6 will allow about 2,5 Tb for the 'user' (roughly 1 Tb will
be consumed by the parity information of RAID6).

How will this 2,5 Tb space present itself at the time of initial
install of FreeBSD?
Will this be a single 'disk'  ad0 ? .. correct or not (then what)?

If FreeBSD is to put on the system as only operating system (Fdisk:
"A = Use Entire disk"), then will the BSD-partitions will show up as
ad0a (/), ad0b (swap), ad0d (/var) etc... correct or not (then what)?

Page 427 of the FreeBSD handbook states that due to the use of 32-bit
integers to store the number of sectors is limited to 2^32 -1 sectors/disk = 2 TB. A layout could be a / 1Gb, b swap, d /root 20 Gb, (a /root partition is from an example of someone who
claims that at boot FreeBSD checks the partions in background except
for the / partition, by keeping / as small as possible, the time to
boot can be mimimized .. correct? but will /root ever be something
big ??)
e /tmp 20 Gb, f /var 20 Gb, g /usr 20 Gb this leaves 2420 Gb which is more than 2 Tb, so you can't put all that in 1 filesystem h /home, you will need to split that in 2
BSD-paritions, but since you can't have more that 8 BSD-partitions
(highest BSD-partition letter is h), you need to give up at least
one of d, e, f, g. ... correct or not (then what)?

What is the best scheme of BSD-partitioning in this case?
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