The man page on date has an example showing how to get an output showing the number of seconds since the Epoch.
date -j -f "%a %b %d %T %Z %Y" "`date`" "+%s" There is an envokation of date embedded in this command of date +%s I was curious as to what this command does so I tried the long form and then the short form with: date -j -f "%a %b %d %T %Z %Y" "`date`" "+%s" >f0 date +%s >f1 I then compared the outputs of f0 and f1 and they are identical. What does the long form of this command give us that date +%s fails to do? Nothing is broken, here. I am just curious. Thank you. Martin McCormick WB5AGZ Stillwater, OK Systems Engineer OSU Information Technology Department Telecommunications Services Group _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"