> I am trying to run a php script from the cron tab and these are the errors I > receive: > > > /usr/local/bin/php php -q /home/xxxx/ripper.php result > Could not open input file: php > /usr/local/bin/php php -/home/xxxx/ripper.php result > > Could not open input file: php > > /usr/local/bin/php -/home/xxxx/ripper.php result > > This script must be called from the command line. > > Running Freebsd 8.0, Php 5.2.12 > I have chmod the script 644 still no luck tried it chmod 777 still no luck. > I have goggled this problem and followed the tutorials but still no luck. > Any ideas how I can get the script to run? > I can run run it from the command line without any problems.
Instead of /usr/local/bin/php php -q /home/xxxx/ripper.php try /usr/local/bin/php -f /home/xxxx/ripper.php or just /usr/local/bin/php /home/xxxx/ripper.php You can also try a script like this one: #!/usr/local/bin/php -f <?php echo "foo\n"; ?> And running it like this: /home/xxxx/ripper.php after chmod'ing it to be executable. _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"