in message <87d3vgmj1s....@cjlinux.localnet>,
wrote Carl Johnson thusly...
>
> Carl Johnson <ca...@peak.org> writes:
>
> > Carl Johnson <ca...@peak.org> writes:
> >
> >> vogelke+u...@pobox.com (Karl Vogel) writes:
> >>
> >>>>> On Thu, 24 Jun 2010 09:24:39 +0800,
> >>>>> Aiza <aiz...@comclark.com> said:
> >>>
> >>> A> Receiving a variable from the command line that is suppose
> >>> A> to contain
> >>> A> numeric values.  How do I code a test to verify the content
> >>> A> is numeric?
> >>>
> >>> The script below will work with the Bourne or Korn shell.
> >>> Results for "0 1 12 1234 .12 1.234 12.3 1a a1":
> >>>
> >>>      0 is numeric
> >>>      1 is numeric
> >>>      12 is numeric
> >>>      1234 is numeric
> >>>      .12 is numeric
> >>>      1.234 is numeric
> >>>      12.3 is numeric
> >>>      1a is NOT numeric
> >>>      a1 is NOT numeric
> >>
> >> You might want to try testing "123..45".
> >> I tried changing:
> >>>    if expr "$arg" : "[0-9]*[\.0-9]*$" > /dev/null
> >> to:
> >>     if expr "$arg" : "[0-9]*\.*[0-9]*$" > /dev/null
> >> but it still claims that it is numeric, so *I* must be missing
> >> something.
> >
> > I just realized that I had a stupid mistake there and should
> > have used:
> >      if expr "$arg" : "[0-9]*\.[0-9]*$" > /dev/null
> And of course that was another stupid mistake that I didn't test
> properly.  I really wanted 0 or 1 decimal points, so I wanted
> '\.\?', except that FreeBSD expr doesn't recognize '\?'.  I
> finally ended up with the following which seems to work as *I*
> expected it to work:
>     if expr "$arg" : "[1-9]*\.\{0,1\}[0-9]*$" > /dev/null

That regex considers "." a number but not "0.9" (this one seems to
be due to typo) nor a negative number.

I would personally to use egrep or awk (printf "%s" "${arg}" | egrep
"${regex}" [0]) instead of expr.


  - parv


  [0] Compact regex ....

      #  Matches a number, either positive (without '+' sign) or
      #  negative, which is either a whole number; or a real number
      #  ending with decimal point, or a real number with or without
      #  leading digits before the decimal point.
      ^
      -?
      (
        [0-9]  [.]? [0-9]*
          |
        [0-9]? [.]  [0-9]+
      )
      $

    ...by removing whitespace before use.


-- 

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