In article <4c2d2839.3040...@comclark.com> you write:
>I have a file containing this
>
>drwxrwxr-x 14 89987 546 512 Jun 6 2009 7.2-RELEASE
>drwxrwxr-x 14 89987 546 512 Mar 23 04:59 7.3-RELEASE
>drwxrwxr-x 13 89987 546 512 Nov 23 2009 8.0-RELEASE
>drwxrwxr-x 13 89987 546 512 Jul 1 04:56 8.1-RC2
>
>I want to strip off everything to the left of the release
>version so I end up with this.
>
>7.2-RELEASE
>7.3-RELEASE
>8.0-RELEASE
>8.1-RC2
>
>How would I code to do this?
sed -e 's/.* //' firstfile > secondfile
awk '{ print $9}' firstfile > secondfile
There are far more complicated methods, too.
R's,
John
_______________________________________________
freebsd-questions@freebsd.org mailing list
http://lists.freebsd.org/mailman/listinfo/freebsd-questions
To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"
