Chuck,
I forgot to add:
> Nope. statclock() is fired off periodically (with
> some fuzz, to avoid clever games by processes trying to
> avoid being sampled) to update the stats for the currently
> running process.
Which would mean that a process that is occupying memory but doesn't happen to
be running on that clock tick doesn't have its memory counted toward the total
... right?
Mark
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