in message <[email protected]>, wrote Tim Daneliuk thusly... > > On 06/07/2012 12:19 AM, Parv wrote: > > in message<[email protected]>, > > wrote Tim Daneliuk thusly... > >> > > ... > >> Within a makefile, I need to assign the name of a program as > >> in: > >> > >> FOO = "bar". > >> > >> The problem is that 'bar' may also be know as, say, "bar.sh". > > ... > >> Is there a simple way to determine which form "bar" or "bar.sh" > >> on on a given system *at the time the make is run*? If both > >> exist, I will pick one arbitrarily, > > ... > >> For example I don't think this works when both are there: > >> > >> FOO = $(shell `which bar bar.sh) > > > > Modify the subshell command to ... > > > > which bar bar.sh | head -n 1 > > > > > > ... as in (for FreeBSD make) ... > > > > shell=`which zsh sh tcsh csh 2>/dev/null | fgrep -v 'not found' | head > > -n 3` ... > Thanks.
Happy to help. > I came up with something similar, but I think your recipe is a bit > more elegant ... It was "If both exist, I will pick one arbitrarily ... " that helped much in modification of the original. - parv -- _______________________________________________ [email protected] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "[email protected]"
