Olivier Nicole <olivier.nic...@cs.ait.ac.th> wrote: > On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline <kl...@thought.org> wrote: > > apologies up front for this math type quandary. I had it in > > a std C program, but 3+ hours of grepping havent found it. > > I would have bet my last cent that I had a summary Somewhere, > > but cant find that either. > > > > here is the problem as best I can remember it. > > > > let's say that john is 8 and his older friend, jim, is 22. > > how much older is exact percentage terms is jim? > > That should be 22/8=2.75 > Jim is 275% older than John

No, a subtraction is needed if we wish to use the term "older". Suppose Jim were 9; the above approach would give 9/8 => 1.125 so Jim is 113% older than John, which is clearly wrong (although one could correctly say in that case that John's age is 113% of Jim's age). I think the OP is probably looking for ((22 - 8) * 100 + (8/2)) / 8 which will give the answer directly as a correctly-rounded integral percentage. (For a fractional percentage, use floats instead of ints and omit the (8/2) part -- but in that case you probably also want to express the ages in something other than whole years.) _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"