On Fri, 18 Jan 2013, Fbsd8 wrote:
In a script in am working on I need to find out the allocated
size of a sparse file.
The only command that comes to mind is "ls -lh"
The "du -h" command is not appropriate because it will show
the occupied size and not the allocated size.
I don't know how to parse out to the position in the output of that
"ls -lh" command to pickup the file size value.
Is there some other way to do this?
To parse it out, I've used something like:
$ ls -lh npviewer.bin.core | cut -d \ -f 9
186M
After the backslash are two spaces: one being the space that's being
escaped to make it the delimiter, the other to separate the options.
The number after the '-f' determines which "field" of the output is
displayed, which may vary.
HTH.
--
Chris Hill [email protected]
** [ Busy Expunging </> ]
_______________________________________________
[email protected] mailing list
http://lists.freebsd.org/mailman/listinfo/freebsd-questions
To unsubscribe, send any mail to "[email protected]"
