In the last episode (Aug 11), Matthew Graybosch said:
> On Mon, 2003-08-11 at 17:49, Constantine wrote:
> > I am writing a script, which involves unzipping some files. I would
> > have to unzip 4 different zip-files from some directory, and I
> > would need to unzip them to the directory, which would have the
> > same name in it as the original zip-file, i.e. I would like to run
> > something like "ls *.zip", have each file name recorded in some
> > variable, and do a loop like "unzip
> > $filename[$i] -d $filename[$i].unzipped/". Can someone help me with the 
> > code? How can I put the results of a command to a variable?
> The following assumes you have the bash port installed. Just change
> the ARCHIVE_DIR variable to the full path of the directory in which
> you have your zip files. Make sure to save this code to a file in
> "~/bin". I suggest pasting the following code into "~/bin/".

Note that this script runs just fine with /bin/sh, so you don't need

        Dan Nelson
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