Jimmy MÃkelà | Loopia Webbhotell AB wrote:
Hi
I'm trying to convert a date from one timezone into another using the date-command, but I can't seem to get it to work.
The problem can be illustrated as below, though in reality I get the date from another source of course, otherwise I wouldn't have to do this.
Take a date in some timezone other than your own, in this example I generate the current time in UTC:
TZ=UTC date +"%d %b %Y %H:%M:%S %z"
28 Nov 2004 12:02:18 +0000
Try to use date -j to convert a date of this format into the default display-format:
TZ=CET date -j -f "%d %b %Y %H:%M:%S %z" "28 Nov 2004 12:02:18 +0000"
Warning: Ignoring 5 extraneous characters in date string (+0000) Sun Nov 28 12:02:18 CET 2004
The result is wrong of course because the timezone is ignored even though i specify %z in the format-string. The date in CET should be 13:02:18.
Now the question; does anyone know why the %z is ignored? Am I missing something, and if so what?
The man-page for the -f parameter states "Parsing is done using strptime(3)." and since strptime allows %z I was assuming that the example above should work.
I would be really thankful for some help in getting around this.
Thanks in advance.
Best regards, Jimmy MÃkelÃ
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Try the following: 1. Output date in seconds from epoch SECONDS=$(date ... "+%s") 2. Change the time zone. TZ=CET export TZ date -r $SECONDS
Best regards, Alexander Derevianko. _______________________________________________ [EMAIL PROTECTED] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "[EMAIL PROTECTED]"
