On Tuesday 19 February 2013 23:26:19 Aman Sawrup wrote:
> I believe the amount of memory reserved needs to be much higher.  For 
> example, if sizeof(struct usb_page) is 16 bytes, then for n_frbuffers of 
> 128 and parm->bufsize of 131072, we need the following amount of memory 
> reserved:
> 
> parm->bufsize / USB_PAGE_SIZE * n_frbuffers * sizeof(struct usb_page)
> = 131072 / 4096 * 128 * 16
> = 65536

Hi,

The parm->bufsize is shared for all frbuffers, so the formula should be 
correct. In your computation you assume that parm->bufsize gives the maximum 
for each frbuffer. That is not the case.

That means, when you configure bufsize, you must not exceed that size as a 
total when setting up frames. This include all transfer types. I think there 
are asserts for that so you should get a panic fairly quickly.

--HPS
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