Hi!

> I just noticed a MEM /c I ran on that HDD Feb 2008.  Why do the
> available memory start out differently.  There is small difference
> in total RAM size, but by then doesn't DOS not care?

>    SYSTEM      17,344   (17K)     10,992   (11K)      6,352    (6K)
>    HIMEM        2,704    (3K)      2,704    (3K)          0    (0K)
>    COMMAND      3,648    (4K)      3,024    (3K)        624    (1K)
...
>    LBACACHE    20,432   (20K)          0    (0K)     20,432   (20K)
...

> Conventional          611K        17K       594K
> Upper                 152K        87K        65K

That is a very small "total RAM" (611k) Either you load some
driver before DOS (e.g. LBA helper for big HDD on old BIOS)
or you have a virus loaded before DOS or you have a driver or
virus inside DOS which allocates RAM by reducing the "total".

> Same HDD, different MB:

>    SYSTEM      17,328   (17K)     10,992   (11K)      6,336    (6K)
>    HIMEM        2,704    (3K)      2,704    (3K)          0    (0K)
>    LBACACHE    20,464   (20K)        336    (0K)     20,128   (20K)
>    COMMAND      4,064    (4K)      3,024    (3K)      1,040    (1K)
...

In this version, LBACACHE uses TUNS, but the stack is small.
I assume this is not the current version of LBACACHE yet ;-)

> Conventional          639K        37K       602K
> Upper                  88K        87K         1K

Note that this other (newer) mainboard leaves less space
for DOS upper memory. On the other hand, 639k total is a
very normal value: It typically means 640k minus 1k for
extra BIOS data area. Extra as opposed to 40:xx (0.25k).

Eric




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