Eric Auer wrote:
> Hi!
> 
>> I just noticed a MEM /c I ran on that HDD Feb 2008.  Why do the
>> available memory start out differently.  There is small difference
>> in total RAM size, but by then doesn't DOS not care?
> 
>>    SYSTEM      17,344   (17K)     10,992   (11K)      6,352    (6K)
>>    HIMEM        2,704    (3K)      2,704    (3K)          0    (0K)
>>    COMMAND      3,648    (4K)      3,024    (3K)        624    (1K)
> ...
>>    LBACACHE    20,432   (20K)          0    (0K)     20,432   (20K)
> ...
> 
>> Conventional          611K        17K       594K
>> Upper                 152K        87K        65K
> 
> That is a very small "total RAM" (611k) Either you load some
> driver before DOS (e.g. LBA helper for big HDD on old BIOS)

I posted the info on the MBs.  Would you consider either of them "old"?

> or you have a virus loaded before DOS or you have a driver or
> virus inside DOS which allocates RAM by reducing the "total".

How would I chase that?
> 
>> Same HDD, different MB:
> 
>>    SYSTEM      17,328   (17K)     10,992   (11K)      6,336    (6K)
>>    HIMEM        2,704    (3K)      2,704    (3K)          0    (0K)
>>    LBACACHE    20,464   (20K)        336    (0K)     20,128   (20K)
>>    COMMAND      4,064    (4K)      3,024    (3K)      1,040    (1K)
> ...
> 
> In this version, LBACACHE uses TUNS, but the stack is small.
> I assume this is not the current version of LBACACHE yet ;-)

No.  As I said that was back in Feb 2008.
> 
>> Conventional          639K        37K       602K
>> Upper                  88K        87K         1K
> 
> Note that this other (newer) 

No, that is the older, that I am calling previous.

> mainboard leaves less space
> for DOS upper memory. On the other hand, 639k total is a
> very normal value: It typically means 640k minus 1k for
> extra BIOS data area. Extra as opposed to 40:xx (0.25k).

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