ALAHYANE Rachid wrote:
Ok so, my end goal is to use the ipa methods with xml-rpc as following,
* ipaServer : my ipa server, used to authenticate users and serves
response for xml-rpc calls from rpcServer
* rpcServer : this host is my xml-rpc server, I installed freeipa
libraires on it, and an apache server with mod_python and mod_auth_kerb.
This hosts will be used as a client ipa, It is for these reasons that i
used `account.py` from within apache.
* myClient : this host is the one which will make the rpc calls to
rpcServer.
NB : 'account.py' is called by xmlrpchandler (it is my python handler)
when getUserInfos is called by myclient .
Can you set LogLevel debug on the rpcServer web server and see if you
get a backtrace (or look in /var/log/httpd/error_log, you may already
have one).
What is strange is that this code works fine standalone. Can you show us
all the code in your xmlrpchandler?
BTW, your English is fine :-)
rob
Example :
myClient calls the remote.account.getUserInfos(u'admin'), rpcServer (in
mode client) intercepts this call and forwards it to the ipaServer. This
last one sends the response to rpcServer (via xml-rpc) and then
rpcServer responds to myClient.
this is my configurations :
== On rpcServer ==
--------- httpd conf ------------
<Files "xmlrpc">
## python conf
# ....
SetHandler python-program
PythonHandler xmlrpchandler
PythonDebug on
</Files>
------------------------------------
the handler xmlrpchandler calls the following method when the client
requests for the remote method getUserInfos().
--------- account.py ------------
def getUserInfos(user_name, env=None):
from ipalib import api
api.bootstrap_with_global_options(context='webservices')
api.finalize()
# mode Server is False. I am not on the server ipa
api.Backend.xmlclient.connect()
return api.Command.user_show(user_name)
------------------------------------
== On myClient ==
When I call this method from my client, I get this exception :
------------------------------------
<Fault 2: "remote.account.getUserInfos: <type
'exceptions.StandardError'>: API.bootstrap() already called">
------------------------------------
I hope that is clearer now, despite my bad English ;)
---
Meilleures salutations / Best Regards
Rachid ALAHYANE
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