I was experimenting with the number of carriers (8 versus 7) on the
coherent modem yesterday, and it seemed to work well.
I was wondering how the number 7 was decided on, as it seems like an odd
number.
For example, for my purposes, it will be simplified to have 32-bits every
baud. I didn't know how to change the pilots so I just added some opposite
to the end:
1.000000, -1.000000, 1.000000, -1.000000, 1.000000, -1.000000, -1.000000,
1.000000
-1.000000, 1.000000, 1.000000, -1.000000, 1.000000, 1.000000, 1.000000,
-1.000000
The 32-bits also gives you another 4-bits at the vocoder, so you can use
1-bit for text and expand something else by 3 bits, or just have 4-bits for
text. 800 bit/s versus 700.
73, Steve/k5okc
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