> in function gray_render_cubic()
>
> level = 1;
> da = da / ras.cubic_level;
> db = db / ras.conic_level;
> while ( da > 0 || db > 0 )
> {
> da >>= 2;
> db >>= 3;
> level++;
> }
>
> I think da should be divided by conic_level and db by cubic_level
> according to the context, or my mistake.
Hmm. Can you explain how you come to this conclusion? I don't
understand the heuristics either (this is one of the many speed-up
tricks left undocumented by David). If you have a cubic equation like
ax³ + bx² + cx + d
my feeling is that `da' corresonds to the cubic term and `db' to the
quadratic one.
To be more precise: Have you done some comparisons (e.g., using a
profiler) or experienced better rendering results if you exchange
those two values?
Werner
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