> The pitch is positive when the bitmap has a ‘down’ flow,
> and negative when it has an ‘up’ flow.
>
> rows * pitch
>
> When i multiply a negative pitch i will get a negative number of bytes
> right?? or my assumption is wrong?
Simply take the absolute value...
> I would like to read the bitmap->buffer,
>
> for (i=0; i < size ; i++)
>
> printf("%.2x ",slot->bitmap.buffer[i]);
> if size = rows*pitch,
> I got the following data for unicode val 0x40 (which represents @)
>
> I got pitch as 4.
>
> Font Data:00 07 fc 00
> 00 00 00 3f
> ff 80 00 00
> 00 ff ff e0
> 00 00 03 f0
> 01 f0 00 00
> 07 c0 00 78
> 00 00 0f 00
> 00 3c 00 00
> 0e 00 00 1e
> 00 00 1c 07
> c3 8e 00 00
> 3c 0f f3 87
> 00 00 38 3f
> ff 87 00 00
> 70 3c 1f 03
> 00 00
There is something wrong... The number of bytes must be a multiple of
four if you have a pitch value of 4.
> so, 4 bytes represents one row. I got bit map *width as 22*, does
> it mean the glyph data is actually in *3 bytes(22/8) * and the
> otherbyte is for padding?
Yes, it should be like this if you have 8 pixels per byte.
Werner
_______________________________________________
Freetype mailing list
[email protected]
http://lists.nongnu.org/mailman/listinfo/freetype
