I'm trying to use rssserver. The first run worked fine, after a reboot I
receive this error:
================================================================================
Freevo 1.7.4 r10133 started at Sat Nov 17 22:41:10 2007
--------------------------------------------------------------------------------
2007-11-17 22:41:10,614 INFO config.py (477):
logdir: /var/log /var/log/freevo
2007-11-17 22:41:10,615 INFO config.py (478):
staticdir: /var/lib /var/lib/freevo
2007-11-17 22:41:10,617 INFO config.py (479):
cachedir: /var/cache /var/cache/freevo
2007-11-17 22:41:10,619 INFO config.py (498): Loading freevo
configuration file "/etc/freevo/freevo.conf"
2007-11-17 22:41:10,849 INFO config.py (585): Loading local
configuration file "/etc/freevo/local_conf.py"
2007-11-17 22:41:10,886 INFO config.py (983):
overlaydir: /var/cache/freevo/vfs
2007-11-17 22:41:10,909 INFO new process watcher instance
Traceback (most recent call last):
File "/usr/lib/python2.4/site-packages/freevo/helpers/rssserver.py",
line 91, in ?
t = threading.Thread(rssperiodic.checkForUpdates())
File "/usr/lib/python2.4/site-packages/freevo/rssperiodic.py", line
238, in checkForUpdates
for item in rssfeed.Feed(feedSource).items:
File "/usr/lib/python2.4/site-packages/freevo/rssfeed.py", line 42, in
__init__
self.parseFeed(inputSource)
File "/usr/lib/python2.4/site-packages/freevo/rssfeed.py", line 109,
in parseFeed
newItem.type =
getType(re.split('"',re.split("\.",newItem.url)[-1])[0])
File "/usr/lib/python2.4/sre.py", line 157, in split
return _compile(pattern, 0).split(string, maxsplit)
TypeError: expected string or buffer
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