If we take this seriously, which I doubt we should :), I think you'd have to create a tree of probabilities much like monty hall problem. (at least if there isn't a trivial nifty solution!)
So start at the root of the tree, generate a branch for choosing each of the three answers, 33.3% each. Then place three branches at each for choosing that branch: 50% for 25%, and 25% for 50% and 60%. OK, 9 branches. Now go through and add up all the probabilities that represent a right path. So for example, take 25% as the first branch, and look for the 25% in the second branch. Ditto for the other 2 possible paths. This route gives 33.3% as the solution. Hmm.. The other approach is to simply say a, b, c, d are the choices which gives the 25% Naturally the last approach is to say its a trick, or word game, or very subtle problem statement. On Sat, Oct 29, 2011 at 9:44 AM, Owen Densmore <[email protected]> wrote: > Oops fat fingered earlier email. I think this, as Tyler sez, is tricky > because of the double 25. You have a 50% chance of 25, but only 25% of the > other two. Like the Monty Hall, I'd like to hear a pro reason through to > the answer. > > On Sat, Oct 29, 2011 at 9:39 AM, Owen Densmore <[email protected]>wrote: > >> >> >> On Sat, Oct 29, 2011 at 9:12 AM, Tyler White >> <[email protected]>wrote: >> >>> The solution depends on how you consider the answers... you can say >>> that there are four unique answers (A, B, C, D) or you could say there are >>> only 3 answers (25%, 50%, 60%). It's a trick question! Hahahah.... >>> >>> Tyler White¹ >>> http://TylerWhiteDesign.com >>> http://twitter.com/Uberousful >>> >>
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