Waldek Hebisch <[EMAIL PROTECTED]> writes: > Martin Rubey wrote:
> > The hard part is to get the asymptotic at infinity :-) As far as I know, > > functions of the form > > > > (a+b*n)^n*q(n) > > > > (a,b are fractions, q a rational function) does not necessarily satisfy a > > difference equation. > > > > Hmm, if f(n) = (a+b*n)^nW_1(n)/W_2(n) and W_2(n+1) and W_2(n) are non-zero, > then we have > > W_2(n+1)*W_1(n)*f(n+1) = (a+n*n)*W_2(n)*W_1(n+1)*f(n) (**) No, I don't think so: (a+b*(n+1))^(n+1) / (a+b*n)^n is not rational. Martin --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "FriCAS - computer algebra system" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/fricas-devel?hl=en -~----------~----~----~----~------~----~------~--~---
