Francois Maltey <[EMAIL PROTECTED]> writes:

> Dear Martin,
> 
> I'm not proud about series but let me tell you what I use in series.
> 
> //1// I only use series in analysis,
> so series with severe variables are very rare for me.
> 
> There are some
> 
> sum(in x^i) sum(in y^j) ... x^i y^j = sum(in y^j) sum(in x^j) ...
> 
> but this use of axiom isn't so fine because it's impossible to find the
> function from this serie in axiom.

Sorry, you need to be more explicit.  What do you mean with

> sum(in x^i) sum(in y^j) ... x^i y^j = sum(in y^j) sum(in x^j) ...

and what do you mean with

> to find the function from this serie in axiom.

???

> //4// Sometime I compute the recip of y=1+x+x^3 arround x=0. So I get a serie
> x=1-y+... Do you know if there is this revert function in axiom.
> It's not recip that is equal to 1/...

Do you mean "revert", i.e. the compositional inverse?

(58) -> res := revert(series(x*(1+ x + x^3), x=0))

   (58)
        2     3     4      5      6       7       8        9         10      11
   x - x  + 2x  - 6x  + 20x  - 70x  + 256x  - 969x  + 3762x  - 14894x   + O(x  )
                        Type: UnivariateTaylorSeries(Expression(Integer),x,0)
(59) -> res + res^2+res^4

                11
   (59)  x + O(x  )
                        Type: UnivariateTaylorSeries(Expression(Integer),x,0)

The series expansion of the root of 1+ x + x^3 itself is ugly, and revert
expects that the constant term vanishes...
 
> //5// I use the coefficient function with polynom.
> By example M(a,0) and N(0,b) are points. Give a vector of (MN) line.
> 
> The equation of the line is
> eqline := determinant matrix [[a,0,1],[0,b,1],[x,y,1]] (equal 0)
> 
> A vector is vector [coefficient (eqline, y, 1), - coefficient (eqline, x, 1)].
> 
> I don't know if this method may be used for series.

*What* do you want to do with series?
> 
> // 6 // An other exercice I do whith series is to find a naive way for
> the serie of the nth root of x=tan x when x -> %plusInfinity.
> 
> So we write cos x * x = sin x and x = n*%pi + %pi/2 - a/n - b/n^2 ...
> You write the two series and find first a, then b, and so.
> 
> ** I don't try this exercice with axiom ** Sometime I do it with maple.

Maybe you could show us how you do this with maple?
> 
> //7// Of corse some series I use aren't around 0 or have a not integer 
> power...
> 
> //8// I quickly try to test the silly series (x^a-a^x) and (x^x - a^a) for a
> fixed a when x is arround a but I can't with axiom.

(67) -> series(x^a-a^x, x=a)

   (67)
                                                  2           a log(a)
                     a log(a)          (- a log(a)  + a - 1)%e                2
     (- log(a) + 1)%e        (x - a) + ------------------------------- (x - a)
                                                      2a
   + 
         2      3    2            a log(a)
     (- a log(a)  + a  - 3a + 2)%e                3            4
     ------------------------------------- (x - a)  + O((x - a) )
                        2
                      6a
                       Type: UnivariatePuiseuxSeries(Expression(Integer),x,a)
(68) -> series(x^x-a^a, x=a)

   (68)
       a log(a)    a                 a log(a)
     %e         - a  + (log(a) + 1)%e        (x - a)
   + 
              2                       a log(a)
     (a log(a)  + 2a log(a) + a + 1)%e                2            3
     ----------------------------------------- (x - a)  + O((x - a) )
                         2a
                       Type: UnivariatePuiseuxSeries(Expression(Integer),x,a)

(69) -> series(x^x-exp(a*log a), x=a)

   (69)
                   a log(a)
     (log(a) + 1)%e        (x - a)
   + 
              2                       a log(a)
     (a log(a)  + 2a log(a) + a + 1)%e                2
     ----------------------------------------- (x - a)
                         2a
   + 
         2      3     2      2      2                2            a log(a)
       (a log(a)  + 3a log(a)  + (3a  + 3a)log(a) + a  + 3a - 1)%e
       -------------------------------------------------------------------
                                         2
                                       6a
    *
              3
       (x - a)
   + 
              4
     O((x - a) )
                       Type: UnivariatePuiseuxSeries(Expression(Integer),x,a)

Martin


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