While in the definition of outputTran I can understand something like this:
x is ['construct,:l] =>
['BRACKET,['AGGLST,:[outputTran y for y in l]]]
I don't understand why
x is ['LIST,:l] => outputTran ['BRACKET,['AGGLST,:l]]
is doing any useful recursive application of outputTran un the list l
since there is no pattern like
x is ['BRACKET,:l]
in outputTran's source code.
Or are these two lines...
[op,:l]:= flattenOps x
...
l:= [outputTran y for y in l]
together with the final
[outputTran op,:l]
doing the trick?
Ralf
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