Why does foo(true, true) not output the same as bar(true, true)? Obviously, => means something
Ralf echo ")r foo.input" | fricas -nosman foo(true, true) (2) "mooTT" foo(true, false) (3) "mooTT" <--- WRONG -- That should be "mooinit". foo(true, true) (4) "mooinit" foo(false, false) (5) "mooinit" ===================================== (6) -> )co foo.spad (6) -> bar(true, true) (6) "TT" <----WRONG -- The "=>" should leave the "then" block, but not return -- from the function. -- Uncomment the line -- str := "TF" -- and the result will correctly be "mooTT" here and "mooTF" for (7). (7) -> bar(true, false) (7) "mooinit" (8) -> bar(false, true) (8) "mooinit" (9) -> bar(false, false) (9) "mooinit" ===================================== aldor -grun -laldor foo.as mooTT mooinit mooinit mooinit -- You received this message because you are subscribed to the Google Groups "FriCAS - computer algebra system" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/fricas-devel. For more options, visit https://groups.google.com/d/optout.
)co foo.spad bar(true, true) bar(true, false) bar(false, true) bar(false, false)
foo(x: Boolean, y: Boolean): String ==
str: String := "init"
if x then
-- str := "TF"
y => (str := "TT")
str := concat("moo", str)
str
foo(true, true)
foo(true, false)
foo(false, true)
foo(false, false)
)abbrev package FOO Foo
Foo: with
bar: (Boolean, Boolean)->String
== add
bar(x: Boolean, y: Boolean): String ==
str: String := "init"
if x then
-- str := "TF"
y => (str := "TT")
str := concat("moo", str)
str
foo.as
Description: application/applix-spreadsheet
