Following up: Is 'devaluate' deprecated and not to be used or is it
intended for some other purpose? If so, what purpose?

On 15 April 2015 at 14:33, Waldek Hebisch <[email protected]> wrote:
> Bill Page wrote:
>>
>> Solved. I found that this works:
>>
>> )abbrev domain TEST Test
>> Test(S:Type): with
>>     name: ()->OutputForm
>>   ==
>>     name() == devaluate(S)$Lisp::OutputForm
>
> This may produce illegal OutputForm.  Ralf recently asked the same
> question.  Answer is: use 'outputDomainConstructor(S)$Lisp'.
>
> PS: There is no need to have parametrized package.  It is enough to
> pass type parameter to 'name'.
>

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