> Is it possible to simplify the matrix M in one shot? Idest all the elements
> of the matrix M in one shot?
As I said, use map for this.
(1) -> m := matrix([[a*log(sin x)-2*log(x), log(x)+log(y)],
[log(x)-log(y), 3*log(x)-4*log(x+3)+log(y)]])
+a log(sin(x)) - 2log(x) log(y) + log(x) +
(1) | |
+ - log(y) + log(x) log(y) - 4log(x + 3) + 3log(x)+
Type:
Matrix(Expression(Integer))
(2) -> logrules:=rule(log(x)+log(y)==log(x*y);
log(x)-log(y)==log(x/y);y*log(x)==log(x^y))
(2)
{log(y) + log(x) + %B == log(x y) + %B,
x y
- log(y) + log(x) + %C == log(-) + %C, y log(x) == log(x )}
y
Type:
Ruleset(Integer,Integer,Expression(Integer))
(3) -> map(c +-> logrules c, m)
+ a +
| sin(x) |
|log(-------) log(x y) |
| 2 |
| x |
(3) | |
| 3 |
| x x y |
| log(-) log(----------------------------)|
| y 4 3 2 |
+ x + 12x + 54x + 108x + 81 +
Type:
Matrix(Expression(Integer))
Note that you defined logrules to work on "Expression(Integer)" (I
abbreviate by E), however "Matrix(E)" is not the same type as E. But the
entries of the matrix are of type E, so "map" does the job of applying
logrules to each entry.
The form "c +-> logrules c" is a lambda expression that locally defines
a function that takes an entry c of the matrix and applies logrules to it.
Hope that helps.
Ralf
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