another problem with numeric evaluations for computing the normal
distribution using the error function.
To my opinion, numeric NV(0.7) directly should return 0.7580363478
Type:
Float
(52) -> NV(x) == (1+erf(x/sqrt(2)))/2
Compiled code for NV has been cleared.
1 old definition(s) deleted for function or rule NV
Type:
Void
(53) -> numeric NV(0.7)
Compiling function NV with type Float -> Expression(Float)
>> Error detected within library code:
Can only compute the numerical value of a constant, real-valued
Expression
(53) -> NV(0.7)
(53) 0.5 erf(0.4949747468) + 0.5
Type:
Expression(Float)
(54) -> numeric NV(0.7)
>> Error detected within library code:
Can only compute the numerical value of a constant, real-valued
Expression
(54) -> erf(0.4949747468)
(54) 0.5160726955_315973
(55) -> 0.5*erf(0.4949747468)+0.5
(55) 0.7580363478
Type:
Float
> --
> Mit freundlichen Grüßen
>
> Johannes Grabmeier
>
> Prof. Dr. Johannes Grabmeier
> Köckstraße 1, D-94469 Deggendorf
> Tel. +49-(0)-991-2979584, Tel. +49-(0)-151-681-70756
> Tel. +49-(0)-991-3615-141 (d), Fax: +49-(0)-3224-192688
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