On 5 December 2016 at 12:31, Bill Page <[email protected]> wrote:
>
> The collection "subgroups of the symmetric group of S" do not form a
> group, rather they ARE groups in-and-of themselves. To be a Group a
> domain needs to export some multiplication operator * that acts on
> members of the domain and an identity 1 for that operation. In this
> case the members of the domain are groups they are not elements of
> some group.
>

Sorry, of course I did not intend to omit the need to export an
inverse operator presumed to satisfy the usual requirements.

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