I saw a math olympiad problem:
solve 27^x = 1/x
The solution is rather simple, although not completely trivial.
Solution: x = 1/3.
I tried to solve this with fricas, but it can't fins a solution.
(1) -> solve(27^x = 1/x, x)
(1) []
Type: List(Equation(Expression(Integer)))
On my iPad I tried it with PocketCAS (based of giac), and it does find a
slution, although not an exact one.
solve(27^x = 1/x, x)
->[exp(-LambertW(ln(27)))]
which is correct, but it calculates it approximately 0.3333333333
Is there a way to get this result in Fricas, preferably exact?
--
Pieter van Oostrum <[email protected]>
www: http://pieter.vanoostrum.org/
PGP key: [8DAE142BE17999C4]
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