Zgleda ne znam več niti prepisovat...
Mišljeno je bilo p_0 = (1 - ro) / (1 - ro^3) = 1 / (1+ro+ro^2)
----- Original Message -----
From: "Matjaž Horvat" <[EMAIL PROTECTED]>
To: "FRIClist" <[email protected]>
Sent: Wednesday, June 21, 2006 9:02 AM
Subject: Re: [Friclist] MIS
To je ista resitev.
LP,
Matjaz
On Tue, 2006-06-20 at 19:26 +0200, ... wrote:
Mraz je to nalogo reševal na dva nacina:
(1.) Sistem obravnavamo kot M/M/1/2 in dobimo p_0 = (1 - ro) / (1 - ro^2)
(2.) M/M/1/1 ... p_0 = 1 / (1 + ro)
Lp
Rok
----- Original Message -----
From: "Samo Šela" <[EMAIL PROTECTED]>
To: "FRIClist" <[email protected]>
Sent: Tuesday, June 20, 2006 6:48 PM
Subject: Re: [Friclist] MIS
3.10 nalog iz vaj, ki smo jih delali pri Mrazu. Koliko imate resitev?
Ce gledam vaje od drugega asistenta, je resitev drugacna?!?
lp,
Samo
On 6/20/06, Matjaž Horvat <[EMAIL PROTECTED]> wrote:
> Kako si pa to uspel predvidit? ;)
>
> Pa 2006 si mislu, ane?
>
> LP,
> Matjaz
>
> On Tue, 2006-06-20 at 09:07 -0700, Marko Kotar wrote:
> > Predvidevam da bo na ispitu 4. naloga tega ispita (13.6.2005). Naloge
> > se
> > namrec ponavljajo. . Jo kdo zna resit?
>
>
>