Zdravo, mi zna kdo razjasni pro računanju H(z).
Npr pri nalogi iz izpita 2006-06-06 za x(n) = (1/2)^n u(n) - 1/4 (1/2)^n-1 u(n-1) pri drugem členu ali je potrebno spremenit 1/4 v 1/2*1/2 in dati 1/2 členu (1/2)^n-1 ali ne??? Zakaj?? Jasno je da se naredi Time shifting ampak ali je terba dodat tudi 1/2 da se stvar lahko zračuna?? pls odgovor, ker sem že čist zmešan Lp jan -- Macs are for those who don't want to know why their computer works. Linux is for those who want to know why their computer works. DOS is for those who want to know why their computer doesn't work. Windows is for those who don't want to know why their computer doesn't work.
