whoops - i forgot that too...it sounded not quite right when i typed it
Cheers
Bert

No. of lines = #ListLen(mystring, chr(13) & chr(10))#

> -----Original Message-----
> From: BOROVOY Noam [mailto:[EMAIL PROTECTED]]
> Sent: 10 May 2001 13:39
> To: Fusebox
> Subject: RE: Slightly OT question ...
> 
> 
> Bert,
> 
> Just a quick correction - the list of delimiters is a set of delimiter
> characters - it itself is not comma delimited... 
> (no need to either as each item is a single char)
> 
> so your code below would also count all commas in the mystring...
> 
> HTH,
> Noam
> 
>       ----------
>       From:  Bert Dawson [SMTP:[EMAIL PROTECTED]]
>       Sent:  Thursday, 10 May 2001 12:01
>       To:  Fusebox
>       Subject:  RE: Slightly OT question ...
> 
>       Better way would be to use a comma delimited list of 
> delimiters - i
> forgot
>       you could have more than one:
> 
>       <cfset mydelimiters = chr(13) & "," & chr(10)>
> 
>       No. of lines = #ListLen(mystring, mydelimiters)#
> 

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