BooK wrote: > So we print $_ multiplied by 1 if all of those have > 1 as their low-order > bit. And by 0, if any of those numbers is even.
Can someone explain to my poor ignorant head what "low-order bit" means? I'm guessing it has something to do with the '&' operator. Be gentle. > ~$. is odd if $. is even What is this? Tell me more, I'm lost. TIA, --Dave
