Bart Lateur said:
> On Wed, 27 Nov 2002 04:41:13 +0000, Paul Makepeace wrote:
>
>>$ perl -Mstrict -le 'print "one" if (my $d = "1") && $d'
>>
>>[or indeed if ((my $d = "1") && $d) {...} ]
>>
>>perl apparently doesn't consider $d exists by the second $d and issues
>> an error. Can someone explain this? (Esp. in light of all this sequence
>> point talk.)
>
> Let me show another example.
>
> my $d = 'outside';
> print do {
> (my $d = 'inside') && $d;
> };
>
> or even
>
> my $d = 'inside' and $d;
>
> instead.
>
> These both print 'outside' (as well as producing a warning about the
> "=" in the conditional, because the RHS is a constant), so, even though
> the inner scoped $d got assigned to already, in the rest of the same
> statement, it's still the outer scoped $d that is visible.
Yes, this is a feature, and is documented in perlsub.
It lets you write
my $d = $d;
should you so wish.
--
Paul Johnson - [EMAIL PROTECTED]
http://www.pjcj.net
