oups, in fact i can handle that as a class
dim hClass as Class dim s as String hClass = Classes["MyModuleName"] For each s in hClass.Symbols PRINT s & iif(hClass[s].Kind = Class.Method, " ==> is a Method", "") Next Sorry 2008/11/23 Fabien Bodard <[EMAIL PROTECTED]>: > I want to call a module function dynamiquely > > > in the idea it is that : > > Modules [sMyModule].Functions[sMyFunction](param) > > Please help me quikly ... it really stop me. I know how to do with > class but with module ? > > is a module a class ? (i don't remember) > > Fabien > ------------------------------------------------------------------------- This SF.Net email is sponsored by the Moblin Your Move Developer's challenge Build the coolest Linux based applications with Moblin SDK & win great prizes Grand prize is a trip for two to an Open Source event anywhere in the world http://moblin-contest.org/redirect.php?banner_id=100&url=/ _______________________________________________ Gambas-user mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/gambas-user
