Am 28.07.2017 um 22:55 schrieb PICCORO McKAY Lenz: > in the following code: > > strinchar = Mid(strinchar, 1, InStr(strinchar, ")", -1) - 1) > > IDE said error invalid argument, but if i do:
No, the IDE says nothing: Public Sub Test() Dim strinchar As String Dim psotionlen As Integer ' ------------------------------------------------- 1 strinchar = "strat)edn1" strinchar = Mid(strinchar, 1, InStr(strinchar, "u", -1) - 1) Print strinchar ' ------------------------------------------------- 2 strinchar = "strat)edn1" psotionlen = InStr(strinchar, ")", -1) - 1 strinchar = Mid(strinchar, 1, psotionlen) Print strinchar ' ------------------------------------------------- 3 ' but the only thing this does is (AFAIK) strinchar = "strat)edn1" Print Left(strinchar, Len(strinchar) - 1) End Result is: strat)edn strat)edn strat)edn :-) Maybe you should write and code a little slower. ;-) Alles Gute Christof Thalhofer -- Dies ist keine Signatur
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