Ah, saw an issue in my code. Here is a fix below.
Smiles,
Cara :)
---
On Mar 1, 2014, at 6:38 PM, Cara Quinn <caraqu...@caraquinn.com> wrote:
Hi John,
Here is what I was talking about.
I have not compiled this so please do feel free to shout out if you use it and
it misbehaves! :)
The below function will check the entire array moving in either direction and
return an integer representing the index of the item which meets your criteria.
// pseudo code
pressing up arrow generates -1
pressing down arrow generates 1
int arrow = (int)(value for pressed arrow key);
int currentPosition = position of current item in array;
// for the sake of this note
int tempPosition = currentPosition;
// C++ code
// returns the next position in the array where a qualifying item is
// in either direction
// returns -1 if entire array is checked and no qualifying item is found
int checkArray(int arrow, int tempPosition) {
tempPosition+=arrow;
for(tempPosition;((arrow>0)?(tempPosition < items.size()):(tempPosition >=
0));((arrow>0)?(tempPosition++):(tempPosition--))) {
if(items[tempPosition].status == 2)
return (tempPosition);
else if(tempPosition == currentPosition)
return (-1);
}
checkArray(arrow, ((arrow>0)?(-1):(items.size())));
}
The for statement is conditional so depending on which arrow key is pressed, it
can move either direction.
If the for statement finishes without finding an item with a status of 2, the
function will be called again with the same arrow value and a new starting
position for the loop to start at.
the loop then continues either until an item is found whose status is 2 or the
original position in the array is again reached. If that happens without a
qualifying item being found, then the function returns -1 to show that no items
met your criteria.
Hope this helps.
Smiles,
Cara :)
---
iOS design and development - LookTel.com
---
View my Online Portfolio at:
http://www.onemodelplace.com/CaraQuinn
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https://twitter.com/ModelCara
On Feb 28, 2014, at 4:45 AM, john <jpcarnemo...@comcast.net> wrote:
Ok, here's a slimmed down version of what I'm trying to work with:
//begin code-global
class item
{
string name;//name of the item
int number;//array reference of the item, used for announcements
int status;//status of the item. This is going to be 0, 1, or 2, menus only
activate if status=2
//add extra variables and functions
}
item [] items(x);//array of items
int [] menulist;//array of ints containing the reference value of all items
whose status variables are 2
void buildlist ()
{
//this figures out what items have status at 2
for(counter=1; counter<items.length; counter++)
{
if(items[counter-1].status==2) menulist.insert_list(items[counter-1].number);
}
}
//end code
After this, I will have a menu that will have variables for min and max
position, max being determined by the length of the menulist array. When the
user moves through the menu, it will display only the numbers contained in that
array.
----- Original Message -----
From: Cara Quinn <caraqu...@caraquinn.com
To: Gamers Discussion list <gamers@audyssey.org
Date sent: Thu, 27 Feb 2014 17:49:30 -0800
Subject: Re: [Audyssey] programming advice: menus
HI John,
YOu do not need to create a second array. You can keep a reference to your
position in the first array, and then check dynamically which element to show
next, forward or backward depending on which direction the player moves in the
menu.
You can choose to skip options which do not meet the criteria you do not want.
I'm not saying that creating a second array is a bad idea or anything by the
way, it actually may be desirable to do this depending on how your code is set
up, how large / complex your initial array is, and how much of your sanity you
would like to hold on to. ;)
Just mentioning that both methods are possible.
If you send along some code, it will be easier to give you a better, more
precise response.
Thanks,
Cara :)---
iOS design and development - LookTel.com
---
View my Online Portfolio at:
http://www.onemodelplace.com/CaraQuinn
Follow me on Twitter!
https://twitter.com/ModelCara
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