Finals are best 2 of 3, so the minimum there is 2.
Now, the initial pool is 4 teams.
Win Game 1, and you are in the winner's bracket.
Play the winner of the other game, and win again.
Your game 2 loser and the winner of the losers' bracket game play
each other while you take the day off, the winner to face you in your
third game on the morrow.
Win that game and it is on to the Championship (a minimum of two more
games).
So, 5 is the minimum.
The max? Hmm.
It seems like 7 (add two losses), but I think it is really 8 as there
is an extra game to win as well:
1. Lose Game 1
2. Win Game 2 (losers' bracket)
3. Win Game 3 (against loser of winners' bracket)
4. Win Game 4 (against winner of winners' bracket)
5. Win Game 5 (also against winner of winners' bracket, as it is
double elimination and you just gave it its first loss)
Now, play in the Championship and have it go all three games for 8
total.
-Zeb
On Jun 14, 2010, at 4:16 PM, Helen Huntley wrote:
I think the shortest route is five games if you win them all. If
you lose one along the way to the championship, it could be six or
seven.
--
GATORS: ONE VOICE ON SATURDAY - NO VOICE ON SUNDAY!
1996 National Football Champions | 2006 National Basketball Champions
2006 National Football Champions | 2007 National Basketball Champions
2008 National Football Champions |
Three Heisman Trophy winners: Steve Spurrier (1966), Danny Wuerffel (1996),
Tim Tebow (2007) - Visit our website at www.gatornet.us
