------- Additional Comments From bangerth at dealii dot org 2005-07-23 21:15 ------- No, the standard says that the result for an iterator 'i' in the output range is ((...(*first + *(first + 1)) + ...) + *(first + (i - result))) So arithmetic is done with the data type of the input range. That may be undesirable on occasion, but that's what the standard says. W.
-- What |Removed |Added ---------------------------------------------------------------------------- Status|UNCONFIRMED |RESOLVED Resolution| |INVALID http://gcc.gnu.org/bugzilla/show_bug.cgi?id=22634