for the following test case:
struct A {
virtual int x () {return 1;}
};
struct B: A {
virtual int x () {return 0;}
};
struct C: B{
using A::x;
};
int main()
{
C c;
return c.x();
}
all g++ 4.x will return 1
It seems C++ standard would want to see 0.
Using-declaration introduces the virtual method x() in the class C and
it's supposed to stay 'virtual', whereas g++ seems to treat it as it overrides
the B's method. In other words using-declaration should effectively be
ignored in this case.
quote from the standard:
"
The rules for member lookup (10.2) are used to determine the final
overrider for a virtual function in the scope of a derived class but ignoring
names introduced by using-declarations.
[ Example:
struct A {
virtual void f();
};
struct B : virtual A {
virtual void f();
};
struct C : B , virtual A {
using A::f;
};
void foo () {
C c;
c.f (); // calls B::f, the final overrider
c.C::f (); // calls A::f because of the using-declaration
}
—end example ]
"
--
Summary: incorrect semantics of using-declaration in c++
Product: gcc
Version: 4.2.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: alexey dot starovoytov at sun dot com
GCC build triplet: all
GCC host triplet: all
GCC target triplet: all
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=28748