The following sample code:
program testhexconstant
integer, parameter :: i4_ = Selected_Int_Kind( 9)
! works fine
integer(i4_), parameter :: pos_nan_lower = z"7F800001"
! triggers an error
integer(i4_), parameter :: pos_nan_lower = z"FF800001"
end program testhexconstant
triggers this error:
gfortran -o testhex TestHex.F90
In file TestHex.F90:8
integer(i4_), parameter :: b = z"FF800001"
1
Error: Arithmetic overflow converting INTEGER(8) to INTEGER(4) at (1)
for the gfortran version downloaded today (20061023) from
http://quatramaran.ens.fr/~coudert/gfortran/gfortran-linux.tar.gz
while the previous version that I had installed (dated 20060914) downloaded
from the same place, just works fine with this code.
This hex value should fit nicely anyway in a 4 byte integer, so I don't really
understand what is happening here.
regards,
Jos de Kloe
--
Summary: hexadecimal constant problem
Product: gcc
Version: 4.2.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: fortran
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: kloedej at knmi dot nl
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=29561
