------- Comment #2 from dougkwan at google dot com 2007-06-13 21:25 ------- The address of dest has been passed to memcpy() and the alias analysis considers the varaible to escape. So potentially foo() can see the value of dest if memcpy() stash the pointer somewhere. This is impossible but the compiler cannot prove this so it has to be conservative and treat foo() as a potential reader of dest.
-- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=32327
