[Bug c++/37898] aggregates vs. defaulted deleted functions

[bkoz at gcc dot gnu dot org]

------- Comment #3 from bkoz at gcc dot gnu dot org  2008-12-04 03:46 -------

FYI removing the deleted copy constructor does indeed make this an aggregate.

So:

struct test_type
{
  int i;

  test_type() = default;
  ~test_type() = default;
  test_type& operator=(const test_type&) = delete;
};


void test()
{
  test_type t1 { 1 };

  test_type t2[4] = { {1}, {2}, {3}, {4} };
  test_type t3[4] = { {1}, {2}, {3} };
}


compiles properly in C++0x mode.


-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=37898