The following program is rejected with:

    f => sin
         1
Error: Interfaces don't match in procedure pointer assignment at (1)

However, if one removes the "module m; contains" it is accepted


module m
contains
  function f()
    intrinsic :: sin
    procedure(sin), pointer :: f
    f => sin
  end function f
end module m


-- 
           Summary: procedure-pointer assignment rejected
           Product: gcc
           Version: 4.5.0
            Status: UNCONFIRMED
          Keywords: rejects-valid
          Severity: normal
          Priority: P3
         Component: fortran
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: burnus at gcc dot gnu dot org


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=40451

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