[Bug c/42184] New: Same literal behaves differently as a double than as a long double

[warp at iki dot fi]

One would assume that the following program prints the same number four times,
but instead "1 0 1 0" is printed. I compiled it with options "-std=c99 -lm".

#include <stdio.h>
#include <math.h>
#include <stdlib.h>

int main(void)
{
    long double value1 = 1.6646342e21;
    long double value2 = 1.6646342e21L;
    long double value3 = strtod("1.6646342e21", NULL);
    long double value4 = strtold("1.6646342e21", NULL);
    long double divisor = 1.25L;

    printf("%Lg %Lg %Lg %Lg\n",
           fmodl(value1, divisor), fmodl(value2, divisor),
           fmodl(value3, divisor), fmodl(value4, divisor));

    return 1;
}


-- 
           Summary: Same literal behaves differently as a double than as a
                    long double
           Product: gcc
           Version: 4.3.1
            Status: UNCONFIRMED
          Severity: minor
          Priority: P3
         Component: c
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: warp at iki dot fi
  GCC host triplet: i586-suse-linux
GCC target triplet: i586-suse-linux


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=42184