http://gcc.gnu.org/bugzilla/show_bug.cgi?id=56643
Bug #: 56643
Summary: Failure to match noexcept specifier of friend template
function in template class
Classification: Unclassified
Product: gcc
Version: 4.7.3
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: [email protected]
ReportedBy: [email protected]
The current SVN version of g++ fails to match the noexcept specifier of the
friend declaration and definition of the test template function in the
following code:
template <int N>
struct Test {
template <int M>
friend void test(Test<M>& arg) noexcept(M == 0);
};
template <int N>
void test(Test<N>& arg) noexcept(N == 0) {}
int main() {
Test<0> t;
test(t);
return 0;
}
I get the following error:
g++ --std=c++11 test.cpp
test.cpp: In instantiation of ‘struct Test<0>’:
test.cpp:12:13: required from here
test.cpp:5:17: error: declaration of ‘template<int M> void test(Test<N>&)
noexcept (<uninstantiated>)’ has a different exception specifier
friend void test(Test<M>& arg) noexcept(M == 0);
^
test.cpp:9:6: error: from previous declaration ‘template<int N> void
test(Test<N>&) noexcept ((N == 0))’
void test(Test<N>& arg) noexcept(N == 0) {}
^
The error message seems to suggest that g++ confuses the template parameter of
the friend function declaration and the template parameter of the containing
class (note the 'N' in the line starting with 'test.cpp:5:17: error').
g++ 4.7.2 reports a similar error.
