https://gcc.gnu.org/bugzilla/show_bug.cgi?id=70414
Bug ID: 70414
Summary: Function declaration in other scope: type safety
violation
Product: gcc
Version: 4.8.4
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: [email protected]
Target Milestone: ---
The following code compiles:
-----------------------------------------
#include<iostream>
void t(){
std::cout << "func t()" << std::endl;
}
int main(int argc, char **argv) {
int t();
std::cout << t() << std::endl;
}
-----------------------------------------
Output:
func t()\n6295712
This should not compile in my opinion because the two function declarations are
of different type.
I'm also referring to (I asked this question):
https://stackoverflow.com/questions/36224099/violation-of-type-safety-in-c-with-function-declaration-of-other-type
