https://gcc.gnu.org/bugzilla/show_bug.cgi?id=71463
--- Comment #16 from Milian Wolff <mail at milianw dot de> ---
So how can I silence the warning then for the case I pasted in the first
comment:
~~~~~~~~~~~~~~~+
#include <cstdlib>
template<typename T> struct foo {};
foo<decltype(&::malloc)> emit_unexpected_warning;
int main() { return 0; }
~~~~~~~~~~~~~~~+
Most notably when you take into account that this is only sometimes required
based on the optimization level. Should I simply not use decltype and instead
paste the definition of malloc inline? Or is there a "silent" decltype
alternative I could use?
