--- Comment #7 from Jonathan Wakely <redi at gcc dot> ---
Strictly speaking, unsigned overflow doesn't even exist. "Integer overflow" is
only something that happens for signed integers. Operations on unsigned
integers have defined behaviour, they can't "overflow".

The C++ standard is clear what happens here: "The negative of an unsigned
quantity is computed by subtracting its value from 2^n , where n is the number
of bits in the promoted operand. The type of the result is the type of the
promoted operand."

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